Given the force applied, the magnitude of the force of friction acting on the mass is 2.5 Newton
Given the data in the question;
- Force acting on the object; [tex]F = 10N[/tex]
- Mass of the object; [tex]m = 5kg[/tex]
- Acceleration of the object; [tex]a = 1.5 m/s^2[/tex]
- Force of friction acting on the mass; [tex]F_k = \ ?[/tex]
To determine the magnitude of the force of friction acting on the mass,
From Newton's laws of motion
[tex]F = m\ *\ a[/tex]
Where F is the force applied, m is the mass of the object and a is the acceleration of the object.
Now, we know that Kinetic Friction is always opposite of the direction of motion.
So, in the question, the force applied overcomes the friction to produce an acceleration of [tex]1.5 m/s^2[/tex]
Hence
[tex]F = F_k + ma[/tex]
Where [tex]F_k[/tex] is the kinetic friction
Now, we substitute our given values into the equation
[tex]10N = F_k +\ ( 5kg\ *\ 1.5m/s^2)\\\\10N = F_k +\ 7.5kg.m/s^2[/tex]
We know that, A newton is defined as [tex]1 kg.m/s^2[/tex]
Hence;
[tex]10N = F_k\ *\ 7.5N\\\\F_k = 10N \ -\ 7.5N\\\\F_k = 2.5N[/tex]
Therefore, given the force applied, the magnitude of the force of friction acting on the mass is 2.5 Newton.
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