Answer:
[tex]\displaystyle y=\frac{2}{3}(x+5)+2[/tex]
Step-by-step explanation:
We need to find the equation of the line perpendicular to the line 3x+2y=8 and passes through (-5,2).
The given line can be expressed as:
[tex]\displaystyle y=-\frac{3}{2}x+4[/tex]
We can see the slope of this line is m1=-3/2.
The slopes of two perpendicular lines, say m1 and m2, meet the condition:
[tex]m_1.m_2=-1[/tex]
Solving for m2:
[tex]\displaystyle m_2=-\frac{1}{m_1}[/tex]
[tex]\displaystyle m_2=-\frac{1}{-\frac{3}{2}}[/tex]
[tex]\displaystyle m_2=\frac{2}{3}[/tex]
Now we know the slope of the new line, we use the slope-point form of the line:
[tex]y=m(x-h)+k[/tex]
Where m is the slope and (h,k) is the point. Using the provided point (-5,2):
[tex]\boxed{\displaystyle y=\frac{2}{3}(x+5)+2}[/tex]
