Janice needs to have a gastro-intestinal study. So she is given 375 mg of radiocontrast dye containing Barium-142. The half-life of Ba-142 is 10.6 minutes and its decay is followed by -ray. After one half -life, of Ba-142 remains . After 31.8 minutes , of Ba-142 remains . After half-lives, 11.7 mg of Ba - 142 remains . After minutes , 0.366 mg of Ba - 142 remains. Finally, after approximately 3.5 hours - half-lives , only 0.000358 mg remains . The dye is no longer visible to the Xray and Janice's study is over .

Respuesta :

After one half life, 188mg

46.9 mg of Ba-142

After 5 half lives

After 106 minutes

20 half lives , only 0.000358 mg remains

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The given statement could be filled in as follows:

After one half-life, 188mg

46.9 mg of Ba-142 After 5 half-lives

After 106 minutes 20 half-lives, only 0.000358 mg remains.

What is half-life?

Half-life is described as the meantime necessary of 1/2 of radioactive decomposition's sample to break up.

In the given study,

Amount of Radiocontrast dye [tex]= 375 mg[/tex]

Half-life [tex]= 10.6[/tex] minutes

Therefore,

The amount left post 1 half-life = 188 mg

Now,

The amount left post 5 half-lives [tex]= 46.9 mg[/tex]

Lastly,

The amount left post 20 half-lives [tex]= 0.000358 mg[/tex]

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