At 1 atm, how much energy is required to heat 59.0 g H2O(s) at −22.0 ∘C to H2O(g) at 141.0 ∘C? STRATEGY: Calculate the energy needed for each temperature change or phase change individually. a. The energy needed to heat 59.0 g H2O(s) from −22.0 ∘C to its melting point. b. The energy needed to melt 59.0 g H2O(s) at its melting point. c. The energy needed to heat 59.0 g H2O(l) from the melting point to the boiling point. d. The energy needed to boil 59.0 g H2O(l) at its boiling point. e. The energy needed to heat 59.0 g H2O(g) from the boiling point to 141.0 ∘C. Sum the energies from each step and convert to kilojoules. Step 1. a. Going from −22.0 ∘C to the melting point of H2O (0 ∘C) is a temperature change of 22.0 ∘C. How much energy is needed to heat 59.0 g H2O(s) by 22.0 ∘C if its specific heat is 2.087 J/(g× ∘C)?