A passenger plane is travelling down the runway with a speed of 20\,\dfrac{\text{km}}{\text{h}}20 h km ​ 20, start fraction, start text, k, m, end text, divided by, start text, h, end text, end fraction, then speeds up with constant acceleration over 2.4\,\text{km}2.4km2, point, 4, start text, k, m, end text over 59\,\text{s}59s59, start text, s, end text. We want to find the final velocity of the plane at the moment of take-off. Which kinematic formula would be most useful to solve for the target unknown?

Respuesta :

Given that,

Initial speed, u = 20 km/s

Acceleration of plane, a = 2.4 km/h²

Time, t = 59 s

We need to find the expression to find the final velocity of an object.Let the final velocity is v.

Using the second equation of kinematics:

[tex]\Delta s=ut+\dfrac{1}{2}at^2[/tex]

a is acceleration, [tex]a=\dfrac{v-u}{t}[/tex]

So,

[tex]\Delta s=ut+\dfrac{1}{2}\times \dfrac{v-u}{t}\times t^2\\\\\Delta s=ut+\dfrac{1}{2}(v-u)t\\\\\Delta s=\dfrac{2ut+vt-ut}{2}\\\\\Delta s=\dfrac{vt+ut}{2}\\\\\Delta s=(\dfrac{v-u}{2})t[/tex]

We can use the above formula to find the final velocity (v) of the plane.

Answer: x=(v+v0/2) t

Explanation: khan academy