Answer:
See Below.
Step-by-step explanation:
Steps:
1) Draw the altitude of the triangle from Vertex B to side CA and label it h.
2) Find [tex]\sin(C)[/tex] of the triangle.*
3) [tex]\displaystyle \sin(C)=\frac{h}{a}[/tex]
4) Solve for h.
5) [tex]h=a\sin(C)[/tex]
6) Substitute expression for h into traditional formula for area of a triangle,[tex]\displaystyle A=\frac{1}{2}bh[/tex].
7) [tex]\displaystyle A=\frac{1}{2}ba\sin(C)=\frac{1}{2}ab\sin(C)[/tex]
(We acquire two right triangles after drawing h since it is an altitude. We will use the smaller of the two.)
