Respuesta :
195 g×
1 mol
Ni(OH)
2
92.71
g Ni(OH)
2
×
6.022×
10
23
formula units
mol
=1.27×
10
24
formula units of Ni(OH)
2
Since there are
5
atoms—one
Ni
atom, two atoms of
O
and two atoms of
H
—in each formula unit of
Ni(OH)
2
,
we multiply the number of formula units calculated above by
5
:
1.27×
10
24
formula units of Ni(OH)
2
×
5 atoms
formula unit of Ni(OH)
2
=6.33× 10^ 24 total atoms
The number of total atoms in 195 grams of [tex]Ni(OH)_2[/tex] is[tex]6.30\times 10^{24}[/tex] atoms
Explanation:
Given:
The 195 grams of nickel(II) hydroxide,[tex]Ni(OH)_2[/tex] .
To find:
The total number of atoms in 105 grams of nickel(II) hydroxide.
Solution:
The mass of nickel(II) hydroxide = 195 g
The molar mass of nickel(II) hydroxide = 92.708 g/mol
The moles of nickel(II) hydroxide:
[tex]=\frac{195 g}{92.708 g/mol}=2.10 mol[/tex]
According to the mole concept:
1 mole =[tex]N_A=6.022\times 10^{23} mol^{-1}[/tex]
The number of molecules of nickel(II) hydroxide =
[tex]N=2.10 mol\times 6.022\times 10^{23} mol^{-1} =1.26\times 10^{24} molecules[/tex]
In 1 molecule of nickel(II) hydroxide there is 1 nickel atom, then in N molecules of nickel(II) hydroxide:
[tex]=1\times 1.26\times 10^{24} atom=1.26\times 10^{24} atoms[/tex]
In 1 molecule of nickel(II) hydroxide there are 2 oxygen atoms, then in N molecules of nickel(II) hydroxide:
[tex]=2\times 1.26\times 10^{24} atom=2.52\times 10^{24} atoms[/tex]
In 1 molecule of nickel(II) hydroxide there are 2 hydrogen atoms, then in N molecules of nickel(II) hydroxide:
[tex]=2\times 1.26\times 10^{24} atom=2.52\times 10^{24} atoms[/tex]
The total number of atoms:
[tex]=1.26\times 10^{24} atoms+2.52\times 10^{24} atoms+2.52\times 10^{24} atoms=6.30\times 10^{24} atoms[/tex]
The number of total atoms in 195 grams of [tex]Ni(OH)_2[/tex] is[tex]6.30\times 10^{24}[/tex] atoms.
Learn more about the mole concept here:
brainly.com/question/10165629?referrer=searchResults
brainly.com/question/13314627?referrer=searchResults
