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A body starts with a velocity of 20 m/s, accelerates uniformly for a time t, moves with constant velocity for the same time, and finally decelerates to rest, again taking a time t. Given that the final deceleration is three times the original acceleration, and the total distance travelled is 140 m, find t.

Respuesta :

Answer:

t=0.14s

Explanation:

  • t=
  • [tex] \frac{s}{v} [/tex]
  • t=
  • [tex] \frac{20}{140} [/tex]
  • Where s= speed
  • V=distance
  • And t=time

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