Jane is asked to buy some chickens, dogs and ducks for her farm. The total number of animals she needs to buy is 50. She has a budget of $1500 to spend on $20/chicken, $50/dog, and $30/duck. Additionally, the number of chickens should be equal to that of ducks. Create a system of 3 equations to model the situation. Assume the number of chickens is x, dogs is y and ducks is z.

Respuesta :

Answer:

x = 20, the number of chickens as well as the number of ducks.

........

20 chickens, 20 ducks and 10 Dogs 50-20-20

And...checking

$400 + $600 + $500 = 1500

x the number of chickens as well as the number of ducks

20x + 30x + 50(50-2x) = $1500

-50x = -1000

Step-by-step explanation:

Hope this helps

The system of 3 equations to model the situation are;

x + y + z = 50

20x + 50y + 30z = 1500

x = z

How to write equation?

  • number of chickens = x
  • number of dogs = y
  • number of ducks = z
  • cost of each chicken = 20
  • cost of each dog = 50
  • cost of each duck = 30
  • Total cost = 1500
  • Total number of animals = 50

The equation:

x + y + z = 50

20x + 50y + 30z = 1500

number of chicken = number of ducks

x = z

Therefore, the equations are;

x + y + z = 50

20x + 50y + 30z = 1500

x = z

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