Answer:
v = 22.5 m/s
Explanation:
The speed of the bucket can be found using the following equation:
[tex] V_{f} = V_{0} + at [/tex]
Where:
[tex]V_{f}[/tex]: is the final speed =?
[tex]V_{0}[/tex]: is the initial speed = 0 (starts from rest)
a: is the acceleration
t: is the time = 2 s
We need to find the acceleration, it can be found as follows:
[tex] F = ma [/tex]
Where:
F: is the force = 45 N
m: is the mass = 4.0 kg
[tex] a = \frac{F}{m} = \frac{45 N}{4.0 kg} = 11.25 m/s^{2} [/tex]
Now, the speed is:
[tex] V_{f} = V_{0} + at = 11.25 m/s^{2}*2 s = 22.5 m/s [/tex]
Therefore, the speed that the bucket will have is 22.5 m/s.
I hope it helps you!
