Answer:
[tex]8\frac{-2x}{-2}=\frac{0}{-2}[/tex]
Step-by-step explanation:
[tex]\left(2a^3b^4c^0\right)^3[/tex]
Cube each portion:
[tex]2^3\left(a^3\right)^3\left(b^4\right)^3\left(c^0\right)^3[/tex]
[tex]8\left(a^3\right)^3\left(b^4\right)^3\left(c^0\right)^3[/tex]
[tex]8a^9\left(b^4\right)^3\left(c^0\right)^3[/tex]
[tex]8a^9b^{12}\left(c^0\right)^3[/tex]
[tex]8a^9b^{12}\times1[/tex]
[tex]8a^9b^{12}[/tex]
