Answer:
Step-by-step explanation:
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A golf ball is hit with a club from the ground on a flat surface. The height of the ball, h(t), in feet, t seconds, after it was hit can be modeled by the function h(t)=40t-16t2. After how many seconds does the golf ball strike the ground?
The ball strikes the ground when the height h(t) = 0. To get the time wen the golf ball strikes the ground, we will substiute h = 0 into the modeled equation and calculate t as shown;
h(t)=40t-16t2
0 h(t)=40t-16t2
40t-16t² = 0
add 16t² to both side
40t-16t²+16t² = 0+16t²
40t = 16t²
40 = 16t
divide both sides by 16
t = 40/16.
t = 2.5secs
Hence the golf ball hit the ground after 2.5secs
Answer:
when the ball is hit as 0 second it has a height of 0 feet (because it hasnt done anything yet). The ball's height increases until it reaches its maximum height of 40 feet after 1.25 seconds (40t= 2.5/2). The balls height then decreases until it reaches 2.5 seconds after it was hit.
