Answer: x= 4 ± [tex]\sqrt{-3}[/tex]
Step-by-step explanation:
[tex]x^{2}[/tex] + 8x + 19 = 0 First subtract 19 from both sides
-19 -19
[tex]x^{2}[/tex] + 8x = -19 Now to complete the square on the left side you will divide 8 by 2 and square the number that you will get and add it to both sides. If you divide 8 by 2 you get 4 and 4 squared is 16 .So add 16 to both sides.
x^2 + 8x + 16 = -19 + 16 Now factor the left side
(x+4)^2 = -3 Take the square root of both sides
(x+4) = ±[tex]\sqrt{-3}[/tex]
Subtract 4 from both sides
x = ±[tex]\sqrt{-3} - 4[/tex]
