Answer:
The correct option is A
Explanation:
Generally the force on [tex]q_2[/tex] is mathematically represented as
[tex]F_2 = \frac{ k * q_1 * q_2 }{ x^2}[/tex]
here k is the coulombs constant with value [tex]k = 9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex]
=> [tex]F_2 = \frac{ 9*10^{9} * 10*10^{-9} * 18*10^{-9} }{ 9^2}[/tex]
=> [tex]F_2 = 2*10^{-8} \ N[/tex]
=> [tex]F_2 = 20*10^{-9} \ N[/tex]
=> [tex]F_2 = 20nN[/tex]
The direction is in the positive x-axis because both charge are of the same polarity so the will repel hence [tex]q_2[/tex] will move toward the positive x-axis
