What is m∠PTQ? a. 12 b. 40 c. 50 d. 140
HELP!!!
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Answer:
B. 40°
Step-by-step explanation:
m<PTQ = (x + 28)°
m<RTS = (2x + 16)°
Angle PTQ and angle RTS are vertically opposite angles, therefore, m<PTQ = m<RTS
[tex] x + 28 = 2x + 16 [/tex]
Solve to find the value of x
[tex] x + 28 - 2x = 2x + 16 - 2x [/tex] (subtracting 2x from each side)
[tex] -x + 28 = 16 [/tex]
[tex] -x + 28 - 28 = 16 - 28 [/tex] (subtracting 28 from each side)
[tex] -x = -12 [/tex]
[tex] x = 12 [/tex] (dividing each side by -1)
Find angle PTQ:
m<PTQ = (x + 28)°
Plug in the value of x
m<PTQ = 12 + 28 = 40°