Answer:
[tex] \boxed{ \sf{length \: of \: a \: rectangle = 60 \: yd}}[/tex]
[tex] \boxed{ \sf{width \: of \: a \: rectangle = 10 \: yd}}[/tex]
Step-by-step explanation:
Let the width of a rectangle be 'w'
Length of a rectangle ( l ) = 6w
Perimeter of a rectangle ( P ) = 140 yd
Finding the width of a rectangle
[tex] \boxed{ \sf{perimeter \: of \: rectangle= 2(length + breadth)}}[/tex]
[tex] \dashrightarrow{ \sf{140 = 2(6w + w)}}[/tex]
[tex] \dashrightarrow{ \sf{140 = 2 \times 7w}}[/tex]
[tex] \dashrightarrow{ \sf{140 = 14w}}[/tex]
[tex] \dashrightarrow{ \sf{14w = 140}}[/tex]
[tex] \dashrightarrow{ \sf{ \frac{14w}{14} = \frac{140}{14}}} [/tex]
[tex] \dashrightarrow{ \sf{w = 10}}[/tex]
Width of a rectangle = 10 yd
Now, replacing / substituting the value of w in 6w in order to find the length of a rectangle
[tex] \dashrightarrow{ \sf{length = 6 \times x = 6 \times 10 = 60 \: yd}}[/tex]
Length of a rectangle = 60 yd
Hope I helped!
Best regards! :D
