Answer:
The frequency distribution is
The frequency distribution is
S/N Class limit Frequency
1 0-2 4
2 3 -4 1
3 5-6 2
4 7-8 2
5 9 - 10 0
6 11 - 12 0
The value for value upper class boundary of the fifth class is [tex]CB_5 = 10.5[/tex]
Step-by-step explanation:
From the question we are told that
The lower class limit is 0
The class width is 2
The scores is 8,6,2,4,2,0,2,6,7
The frequency distribution is
S/N Class limit Frequency
1 0-2 4
2 3 -4 1
3 5-6 2
4 7-8 2
5 9 - 10 0
6 11 - 12 0
Generally the upper class boundary of the fifth class is mathematically represented as
[tex]CB_5 = \frac{10 + 11}{2}[/tex]
[tex]CB_5 = 10.5[/tex]
