A jetliner, traveling northward, is landing with a speed of 71.9 m/s. Once the jet touches down, it has 675 m of runway in which to reduce its speed to 11.3 m/s. Compute the average acceleration (magnitude and direction) of the plane during landing (take the direction of the plane's motion as positive).

Respuesta :

Answer:

The value is  [tex]a =  -3.7 \  m/s^2 [/tex]

Explanation:

From the question we are told that

   The  landing speed is  [tex]u =  71.9 \  m/s[/tex]

   The  distance traveled is  [tex]d =  675 \  m[/tex]

    The velocity it is reduced to is  [tex]v  =  11.3 \  m/s[/tex]

   

Generally the average acceleration is mathematically represented as

      [tex]a =  \frac{ v^2  -  u^2 }{ 2 * d }[/tex]

=>  [tex]a =  \frac{ 11.3^2 - 71.9^2 }{ 2 * 675 }[/tex]

=>   [tex]a =  -3.7 \  m/s^2 [/tex]