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Let x be the log to base 2 of 18. Then we can write:
[tex]2^{x}=18[/tex]
Taking logs of both sides gives us:
[tex]x\ log2=log18[/tex]
[tex]x=\frac{log18}{log2}=4.17[/tex]
The answer is 4.17.

Answer:

4.17

Step-by-step explanation:

We have been given an expression [tex]\text{log}_2(18)[/tex]. We are asked to find the value of our given expression.

We can interpret our given expression as 2 raised to some power equals 18 and we need to find that power (x). We can represent our given information in an equation as:

[tex]2^x=18[/tex]

Upon taking natural log of both sides we will get,

[tex]\text{ln}(2^x)=\text{ln}(18)[/tex]

Using property [tex]\text{ln}(a^b)=b\cdot \text{ln}(a)[/tex] we will get,

[tex]x\cdot \text{ln}(2)=\text{ln}(18)[/tex]

[tex]\frac{x\cdot \text{ln}(2)}{\text{ln}(2)}=\frac{\text{ln}(18)}{\text{ln}(2)}[/tex]

[tex]x=\frac{2.8903717578961647}{0.6931471805599453}[/tex]

[tex]x=4.16992500144\approx 4.17[/tex]

Therefore, the value of our given expression is 4.17.