Respuesta :
3 consecutive integers : x, x + 1, x + 2
x + (x + 1) + ( x + 2) = 267...combine like terms
3x + 3 = 267...subtract 3 from both sides
3x = 267 - 3
3x = 264
x = 264/3
x = 88
x + 1 = 88 + 1 = 89
x + 2 = 88 + 2 = 90
the largest will be 90
x + (x + 1) + ( x + 2) = 267...combine like terms
3x + 3 = 267...subtract 3 from both sides
3x = 267 - 3
3x = 264
x = 264/3
x = 88
x + 1 = 88 + 1 = 89
x + 2 = 88 + 2 = 90
the largest will be 90
Answer: 90 → largest consecutive integer
Step-by-step explanation: In this problem, it's telling us that the sum of three consecutive integers is 267 and it asks us to find the largest integer.
Three consecutive integers can be represented as followed.
X → first integer
X + 1 → second integer
X + 2 → third integer
Since the sum of our three consecutive integers is 267, we can set up an equation to represent this.
X + X + 1 + X + 2 = 267
Now, we can simplify on the left side of our equation.
3x + 3 = 267
-3 -3 ← subtract 3 on both sides
3x = 264
÷3 ÷3 ← divide both sides by 3
X = 88
88 → first integer
89 → second integer
90 → third integer
Therefore, the largest consecutive integer is 90.