Respuesta :

3 consecutive integers : x, x + 1, x + 2

x + (x + 1) + ( x + 2) = 267...combine like terms
3x + 3 = 267...subtract 3 from both sides
3x = 267 - 3
3x = 264
x = 264/3
x = 88

x + 1 = 88 + 1 = 89
x + 2 = 88 + 2 = 90

the largest will be 90

Answer: 90 → largest consecutive integer

Step-by-step explanation: In this problem, it's telling us that the sum of three consecutive integers is 267 and it asks us to find the largest integer.

Three consecutive integers can be represented as followed.

X → first integer

X + 1 → second integer

X + 2 → third integer

Since the sum of our three consecutive integers is 267, we can set up an equation to represent this.

X + X + 1 + X + 2 = 267

Now, we can simplify on the left side of our equation.

3x + 3 = 267

      -3     -3   ← subtract 3 on both sides

      3x = 264

      ÷3     ÷3   ← divide both sides by 3

        X = 88

88 → first integer

89 → second integer

90 → third integer

Therefore, the largest consecutive integer is 90.