contestada

Peter has one of each of the following coins in his pocket: a penny, a nickel, a dime, a quarter, and a half-dollar. Four of these coins are taken out of the pocket and the sum of their values is calculated. How many different sums are possible?

Respuesta :

mlarsen5000

Answer:

10

Step-by-step explanation:

This is a combinations problem, involving factorials.

5!/3!*2!=5*4/2=20/2=10

MrRoyal

The different sum of the 4 coins from the list of 5 coins is an illustration of combination or selection. There are 5 different possible sums.

Given

[tex]n = 5[/tex] --- number of coins

[tex]r = 4[/tex] --- coins to be selected to calculate sum

For the sum of the coin value to be calculated, the 4 coins must be selected. This means combination.

So, we make use of:

[tex]^nC_r = \frac{n!}{(n - r)!r!}[/tex]

This gives

[tex]^5C_4 = \frac{5!}{(5 - 4)!4!}[/tex]

[tex]^5C_4 = \frac{5!}{1!4!}[/tex]

Expand

[tex]^5C_4 = \frac{5*4!}{1*4!}[/tex]

[tex]^5C_4 = \frac{5}{1}[/tex]

[tex]^5C_4 = 5[/tex]

Hence, there are 5 different possible sums.

Read more about combinations at:

https://brainly.com/question/15401733

Otras preguntas