4 (hx - 1) -3 (x +h) ≡ 5 (x + k)
Work out the value of h and k
H and k are integer constants

Question

12-08-2020
Mathematics

contestada

4 (hx - 1) -3 (x +h) ≡ 5 (x + k)
Work out the value of h and k
H and k are integer constants

Respuesta :

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ricchad ricchad · Answer 1 · 2020-08-19T16:06:19+02:00

Answer:

4hx - 8x - 3h - 4

k = ------------------------

5

8x + 5k + 4

h = ------------------------

4x - 3

Step-by-step explanation:

4 (hx - 1) - 3 (x + h) = 5 (x + k)

4hx - 4 - 3 (x + h) = 5 (x + k)

4hx - 4 - 3x - 3h = 5 (x + k)

4hx - 4 - 3x - 3h = 5x + 5k add 3h both sides

4hx - 4 - 3x - 3h + 3h = 5x + 5k + 3h simplify

4hx - 4 - 3x = 5x + 5k + 3h add 4 both sides

4hx - 4 - 3x + 4 = 5x + 5k + 3h + 4 simplify

4hx - 3x = 5x + 5k + 3h + 4 subtract 5x from both sides

4hx - 3x - 5x = 5x + 5k + 3h + 4 - 5x simplify

4hx - 8x = 5k + 3h + 4

4hx - 8x - 3h - 4 = 5k

4hx - 8x - 3h - 4

k = ------------------------

5

solving for h;

4hx - 3h = 8x + 5k + 4

h(4x - 3) = 8x + 5k + 4

8x + 5k + 4

h = ------------------------

4x - 3

adioabiola adioabiola · Answer 2 · 2021-11-09T13:43:34+01:00

The value of h and k are h = (8x + 5k + 4) / (4x - 3) and k = (4hx - 8x - 3h - 4) / 5 respectively

Given:

4 (hx - 1) -3 (x +h) ≡ 5 (x + k)

open parenthesis

4hx - 4 - 3x - 3h = 5x + 5k

4hx - 4 - 3x - 3h - 5x - 5k = 0

4hx - 8x - 3h - 5k - 4 = 0

For k

4hx - 8x - 3h - 4 = 5k

[tex]k = (4hx - 8x - 3h - 4) / 5[/tex]

For h

4hx - 8x - 3h - 5k - 4 = 0

4hx - 3h = 8x + 5k + 4

h(4x - 3) = 8x + 5k + 4

[tex]h = (8x + 5k + 4) / (4x - 3)[/tex]

Therefore, the value of h and k are h = (8x + 5k + 4) / (4x - 3) and k = (4hx - 8x - 3h - 4) / 5 respectively

4 (hx - 1) -3 (x +h) ≡ 5 (x + k) Work out the value of h and k H and k are integer constants

Respuesta :

Otras preguntas

4 (hx - 1) -3 (x +h) ≡ 5 (x + k)
Work out the value of h and k
H and k are integer constants