Answer:
It is reduced to the equation of the Theorem of Pythagoras.
Step-by-step explanation:
Any triangle can be modelled by this formula under the Law of Cosine:
[tex]b = \sqrt{a^{2}+c^{2}-2\cdot a\cdot c\cdot \cos B}[/tex]
Where:
[tex]a[/tex], [tex]b[/tex], [tex]c[/tex] - Side lengths, dimensionless.
[tex]B[/tex] - Angle opposed to the side [tex]b[/tex], measured in sexagesimal degrees.
Now, let suppose that angle B is a right angle (90º), so that b is a hypotenuse and a and c are legs. Hence:
[tex]\cos B = 0[/tex]
And the equation is reduced to the form of the Theorem of Pythagoras, that is to say:
[tex]b = \sqrt{a^{2}+c^{2}}[/tex]
