Answer:
The answer is below
Step-by-step explanation:
The points of the triangle are (- 5, 1), (2, 1), (2, - 1). The distance between two points is given by:
[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
The horizontal leg is formed by points with the same y axis. Therefore the points that make up the horizontal leg is (- 5, 1), (2, 1). The Distance of the horizontal leg is:
[tex]Horizontal\ leg=\sqrt{(2-(-5))^2+(1-1)^2}=\sqrt{7^2+0}=7\ units[/tex]
The vertical leg is formed by points with the same x axis. Therefore the points that make up the vertical leg is (2 1), (2, 1-). The Distance of the vertical leg is:
[tex]Vertical\ leg=\sqrt{(2-2)^2+(-1-1)^2}=\sqrt{0+(-2)^2}=2\ units[/tex]
The hypotenuse is gotten using Pythagorean theorem. It is gotten by:
Hypotenuse² = (Horizontal leg)² + (Vertical leg)²
Hypotenuse² = 7² + 2²
Hypotenuse² = 49 + 4 = 53
Hypotenuse = √53
Hypotenuse = 7.28 unit
