Respuesta :
Answer:
Heat = 3138J
Explanation:
In the system, the sample of Copper is releasing heat that produce the increasing in the temperature of water.
Using the equation of calorimeter, we can find the heat released for the sample of copper (The same that is absorbed for the water):
Q = C×m×ΔT
Where Q is heat, C is specific heat (For water: 4.184J/molK), m is the mass of water (50g) and ΔT is change in temperature of water (40°C-25°C = 15°C)
Replacing:
Q = 4.184J/molK×50g×15°C
Q = 3138J is the heat released for the sample of Copper (The same absorbed for the water).
Answer:
heat=3138j
Explanation:
In the system, the sample of Copper is releasing heat that produce the increasing in the temperature of water.
Using the equation of calorimeter, we can find the heat released for the sample of copper (The same that is absorbed for the water):
Q = C×m×ΔT
Where Q is heat, C is specific heat (For water: 4.184J/molK), m is the mass of water (50g) and ΔT is change in temperature of water (40°C-25°C = 15°C)
Replacing:
Q = 4.184J/molK×50g×15°C
Q = 3138J is the heat released for the sample of Copper (The same absorbed for the water).