Answer:
D
Step-by-step explanation:
Given a parabola in standard form, y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]
y = - 4x² - 16x - 12 ← is in standard form
with a = - 4 and b = - 16 , thus
[tex]x_{vertex}[/tex] = - [tex]\frac{-16}{-8}[/tex] = - 2
Substitute x = - 2 into y for corresponding y- coordinate
y = - 4(- 2)² - 16(- 2) - 12 = - 16 + 32 - 12 = 4
vertex = (- 2, 4 ) → D
