Answer:
[tex] \frac{1}{6} [/tex]
Step-by-step explanation:
Total possible outcomes when you rolled the dices= 6*6=36
Outcome with sum as 7:
(1,6) (6,1)
(2,5) (5,2)
(3,4) (4,3)
N( outcomes with sum as 7)= 6
P(sum as 7):
[tex] \frac{n(outcomes \: with \: \: sum \: as \: 7)}{total \: outcome} \\ = \frac{6}{36} \\ = \frac{1}{6} [/tex]
Hope this helps...
Good luck on your assignment..
