Answer:
k = -11
Step-by-step explanation:
Let [tex]p(x) = x^3-6x^2+kx+10[/tex]
And x+2 is a factor of p(x)
Let x+2 = 0 => x = -2
Putting in p(x)
=> p(-2) = [tex](-2)^3-6(-2)^2+k(-2)+10[/tex]
By remainder theorem, Remainder will be zero
=> 0 = -8-6(4)-2k+10
=> 0 = -8-24+10-2k
=> 0 = -22-2k
=> -2k = 22
Dividing both sides by -2
=> k = -11
