Answer:
The degrees of freedom are given by:
[tex] df =n-1= 15-1=14[/tex]
And if we look in the chi square distribution with 14 degrees of freedom and if we find a quantile who accumulates 0.1 of the area in the left we got:
[tex] \chi^2 = 7.790[/tex]
And then the best answer would be:
c. 7.790
Step-by-step explanation:
For this case we know that we are using a one tailed (lower tail) critical value using a significance level of [tex]\alpha=0.1[/tex] and for this case we know that the ample size is n=15. The degrees of freedom are given by:
[tex] df =n-1= 15-1=14[/tex]
And if we look in the chi square distribution with 14 degrees of freedom and if we find a quantile who accumulates 0.1 of the area in the left we got:
[tex] \chi^2 = 7.790[/tex]
And then the best answer would be:
c. 7.790