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In the laboratory, a quantity of I2 was reacted with excess H2 to give 1.26 moles of HI. It is also known that the percent yield of this reaction was 84.0%. How many moles of I2 reacted

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Answer:

1.008moles of iodine

Explanation:

Hello,

This question requires us to calculate the theoretical yield of I₂ or number of moles that reacted.

Percent yield = (actual yield / estimated yield) × 100

Actual yield = 1.2moles

Estimated yield = ?

Percentage yield = 84%

84 / 100 = 1.2 / x

Cross multiply and solve for x

100x = 84 × 1.2

100x = 100.8

x = 100.8/100

x = 1.008moles

1.008 moles of I₂ reacted in excess of H₂ to give 1.2 moles of HI

The number of moles of I2 reacted should be 1.008moles of iodine

Calculation of the number of moles:

We know that

Percent yield = (actual yield / estimated yield) × 100

Here

Actual yield = 1.2moles

Estimated yield =  x

And, Percentage yield = 84%

So,

84 / 100 = 1.2 / x

100x = 84 × 1.2

100x = 100.8

x = 100.8/100

x = 1.008moles

Therefore, The number of moles of I2 reacted should be 1.008moles of iodine

Learn more about moles here: https://brainly.com/question/19462659

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