Answer : The mass of [tex]O_2[/tex] produced is, 384 grams.
Explanation : Given,
Moles of [tex]KClO_3[/tex] = 8.00 mol
First we have to calculate the moles of [tex]O_2[/tex]
The balanced chemical equation is:
[tex]2KClO_3\rightarrow 2KCl+3O_2[/tex]
From the reaction, we conclude that
As, 2 moles of [tex]KClO_3[/tex] react to give 3 moles of [tex]O_2[/tex]
So, 8.00 mole of [tex]KClO_3[/tex] react to give [tex]\frac{3}{2}\times 8.00=12[/tex] mole of [tex]O_2[/tex]
Now we have to calculate the mass of [tex]O_2[/tex]
[tex]\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2[/tex]
Molar mass of [tex]O_2[/tex] = 32 g/mole
[tex]\text{ Mass of }O_2=(12moles)\times (32g/mole)=384g[/tex]
Therefore, the mass of [tex]O_2[/tex] produced is, 384 grams.
