A bag contains 5 yellows tickets numbered 1 through 5. The bag also contains 5 green tickets numbers 1 to five. You randomly pick a ticket. It is green or has a number greater than 4. Find the probability of tbhs occuring

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Answer:

[tex]\frac{3}{5}[/tex] or 0.6

Step-by-step explanation:

Given:

Number of yellow tickets = 5

Number of green tickets = 5

Total number of tickets = 5 + 5 = 10

Required:

Find the probability that a randomly picked ticket is green or has a number greater than 4

Use the formula:

P = probability of green tickets + probability of yellow tickets with numbers greater than 4

Yellow tickets with numbers greater than 4 = 1 ticket

Probability of picking a green ticket = [tex] \frac{5}{10} = \frac{1}{2} [/tex]

Probability of picking a yellow ticket with number greater than 4 = [tex]\frac{1}{10}[/tex]

Therefore, probability that a randomly picked ticket is green or has a number greater than 4

= [tex]\frac{1}{2} + \frac{1}{10} = \frac{6}{10}[/tex]

[tex]= \frac{3}{5}[/tex]

Probability that a randomly picked ticket is green or has a number greater than 4 = [tex]\frac{3}{5}[/tex] or 0.6