Answer:
[tex]4.9\ m/sec^2[/tex]
Explanation:
The computation of acceleration of the particle down the slope is shown below:-
data provided in the question
Particle of mass = 1.3 kg i,e sliding down
Inclined = 30 to the horizontal
based on the above information
Force is given by
[tex]N = mg\ cos \theta[/tex] ............ 1
and sliding force is given by
[tex]F = mg\ sin\alpha[/tex]
[tex]a = g(sin\ 30^{\circ})[/tex]
[tex]= 9.8\times \frac{1}{2} m/sec^2[/tex]
= [tex]= 4.9\ m/sec^2[/tex]
Hence, the acceleration of the particle down the slope is 4.9 m/sec^2
