Brittany's kite is flying above a field at the end of 65 m of string. If the angle of elevation to the kite
measures 70°, how high is the kite above Brittany's head?

Respuesta :

Answer:

61.1 m is the correct answer.

Step-by-step explanation:

Given that

Brittany's kite has a string length = 65 m

Angle of elevation of kite = [tex]70^\circ[/tex]

A right angled triangle can be constructed for the given situation.

Please refer to the attached figure.

[tex]\triangle BFK[/tex] in which B is the position of Brittany.

K is the position of kite and

F is the point of field above which the kite is flying.

Given that the side BK = 65m

[tex]\angle B = 70^\circ[/tex]

To find, side FK = ?

We can use sine trigonometric identity to find the value of FK.

We know that :

[tex]sin\theta =\dfrac{Perpendicular}{Hypotenuse}[/tex]

[tex]\Rightarrow sinB = \dfrac{FK}{BK}\\\Rightarrow sin70 = \dfrac{FK}{65}\\\Rightarrow FK = 65 \times 0.94\\\Rightarrow FK = 61.1\ m[/tex]

Hence, the answer is 61.1 m.

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