WILL GIVE BRAINLIEST! NEED QUICK HELP ASAP! Photo added! least common denominator x^3/x^2+4x+4 and -9/x^2+5x+6
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The denominator( s ) we are given are [tex]x^2 + 4x + 4[/tex], and . The first thing we want to do is factor the expressions, to make this easier -
[tex]x^2 + 4x + 4[/tex]
This expression is a perfect square, as ( x )^2 = x^2, ( 2 )^2 = 4, 2 * ( x ) * ( 2 ) = 4x. Thus, the simplified expression should be the following -
[tex]( x + 2 )^2[/tex]
The other expression is, on the other hand, not a perfect square so we must break this expression into groups and attempt factorization -
[tex]x^2 + 5x + 6,\\\left(x^2+2x\right)+\left(3x+6\right),\\x\left(x+2\right)+3\left(x+2\right),\\\left(x+2\right)\left(x+3\right)\\\\Factored Expression = \left(x+2\right)\left(x+3\right)[/tex]
Combining ( x + 2 )^2 and ( x + 2 )( x + 3 ), the expression that contains factors of each is ( x + 2 )^2 * ( x + 3 ), or in other words the LCM.
Solution = [tex]\left(x+2\right)^2\left(x+3\right)[/tex]