Respuesta :
Answer:
The expected number of ticket holders that will fail to show for the flight is 8.34.
Step-by-step explanation:
For each passenger, there are only two possible outcomes. Either they fail to show up to the flight, or they do not. The probability of a passenger not showing up is independent of other passengers. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
3% of passengers fail to show for flights
This means that [tex]p = 0.03[/tex]
The airline sells 278 tickets
This means that [tex]n = 278[/tex]
What is the expected number of ticket holders that will fail to show for the flight
[tex]E(X) = np = 278*0.03 = 8.34[/tex]
The expected number of ticket holders that will fail to show for the flight is 8.34.
