Answer: 360000
Step-by-step explanation:
Given
There are 5 girls and 4 boys
Total no of ways in which 5 girls and 4 boys can be arranged is 9!
and no ways in which atleast two girls are standing next to each other is given by
=Total no of arrangements - No of ways in which each girl is separated by a boy
So, no of ways in which each girl is separated by a boy
[tex]=5! \times 4![/tex]
Therefore total no of ways in which atleast two girls are standing next to each other
[tex]=9!-5!\times 4![/tex]
[tex]=362880-2880[/tex]
[tex]=360000[/tex]