The nth term of a sequence is represented by [tex]\frac{2n^4+25n^2+32n-15}{6n^4+2n^3-11n^2-2n+17}[/tex] . What is the limit of the nth term as x becomes increasingly large?

WILL GIVE BRAINLIEST, PLEASE ANSWER QUICKLY

Respuesta :

Answer:

2n3+8n2-32n=16

Step-by-step explanation:

[tex]2n3 +8n2-32n=16[/tex]