Respuesta :
Answer:
It will sink
Step-by-step explanation:
We first have to find the volume of the pyramid. Then, find the density and compare it to that of water.
The pyramid has a base area of [tex]2 cm^2[/tex] and height is 0.5 cm. The volume of a pyramid is given as:
V = (a * h) /3
where a = base area and h = height of pyramid
Therefore:
V = (2 * 0.5) / 3 = [tex]0.33 cm^3[/tex]
Density is given as:
D = mass / volume
The mass of the pyramid is 1.17 g.
Therefore:
Density = 1.17 / 0.33 = 3.54 [tex]g/cm^3[/tex]
Since its density is greater than that of water, it will sink.
The base should be sink
Calculation of the volume, density:
Since the density of water is 1 gram per cm^3.
The volume is
[tex]V = (a \times h) \div 3[/tex]
Here a = base area and h = height of the pyramid
So,
[tex]V = (2 \times0.5) \div 3 = 0.33cm^3[/tex]
Now
Density is
[tex]D = mass \div volume[/tex]
Since The mass of the pyramid is 1.17 g.
So, the density is
Density [tex]= 1.17 \div 0.33 = 3.54 g/cm^3[/tex]
Since its density is more than that of water, so it will sink.
Hence, we can conclude that The base should be sink
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