The density of water is 1 gram per cm3. An object floats in water


if its density is less than water’s density, and it sinks if its density


is greater than water’s. Will a 1.17 gram pyramid whose base has


area 2 cm2 and whose height is 0.5 centimeters sink or float?

Respuesta :

Answer:

It will sink

Step-by-step explanation:

We first have to find the volume of the pyramid. Then, find the density and compare it to that of water.

The pyramid has a base area of [tex]2 cm^2[/tex] and height is 0.5 cm. The volume of a pyramid is given as:

V = (a * h) /3

where a = base area and h = height of pyramid

Therefore:

V = (2 * 0.5) / 3 = [tex]0.33 cm^3[/tex]

Density is given as:

D = mass / volume

The mass of the pyramid is 1.17 g.

Therefore:

Density = 1.17 / 0.33 = 3.54 [tex]g/cm^3[/tex]

Since its density is greater than that of water, it will sink.

The base should be sink

Calculation of the volume, density:

Since the density of water is 1 gram per cm^3.

The volume is

[tex]V = (a \times h) \div 3[/tex]

Here a = base area and h = height of the pyramid

So,

[tex]V = (2 \times0.5) \div 3 = 0.33cm^3[/tex]

Now

Density is

[tex]D = mass \div volume[/tex]

Since The mass of the pyramid is 1.17 g.

So, the density is

Density [tex]= 1.17 \div 0.33 = 3.54 g/cm^3[/tex]

Since its density is more than that of water, so it will sink.

Hence, we can conclude that The base should be sink

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