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The earth is about​ 12,760 km in diameter and about 150 million kilometers away from the sun. The nearest stars besides the Sun are about 4.3​ light-years away​ (1 ​light-year equals = 9.5 times 10 Superscript 12 Baseline km 9.5×1012 km​). At a scale of 1 to 10​ billion, the Sun would be about the size of a grapefruit. How big and how far away would the Earth be on this​ scale? How far would the nearest stars​ (besides the​ Sun) be?

Respuesta :

Answer:

0.00128 m = ;

15 m;

950000 m (950 km)

Step-by-step explanation:

The scale to be used is 1 to 10​ billion (1 : 10,000,000,000)

The earth is about​ 12,760 km (12760000 m) in diameter and about 150 million km (150000000000 m) away from the sun.

Therefore, using this scale, we just have to divide the diameter and distance of the earth from the sun by 10,000,000,000:

Diameter = 12760000 / 10000000000 = 0.00128 m

Distance = 150000000000 / 10000000000 = 15 m

The nearest stars besides the Sun are about 4.3​ light-years away​ (1 ​light-year equals = [tex]9.5 * 10^{12} km[/tex] = 9500000000000000 m​). Therefore, using the scale:

Distance = 9500000000000000 / 10000000000 = 950000 m = 950 km

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