Answer:
[tex] m =\frac{y_2 -y_1}{x_2 -x_1}[/tex]
And replacing we got:
[tex] m=\frac{8-(-6)}{8-6}= 7[/tex]
And now we can use one of the points and we can find the intercept b like this:
[tex] 8 = 7*8 +b[/tex]
And solving for b we got:
[tex] b = 8 -56 = -48[/tex]
And the line would be:
[tex] y = 7x -48[/tex]
Step-by-step explanation:
For this case we have two points given :
(x1=6,y1=-6) and (x2=8,y2=8)
We can find the line equation given by:
[tex] y = mx+b[/tex]
The slope would be:
[tex] m =\frac{y_2 -y_1}{x_2 -x_1}[/tex]
And replacing we got:
[tex] m=\frac{8-(-6)}{8-6}= 7[/tex]
And now we can use one of the points and we can find the intercept b like this:
[tex] 8 = 7*8 +b[/tex]
And solving for b we got:
[tex] b = 8 -56 = -48[/tex]
And the line would be:
[tex] y = 7x -48[/tex]
