Answer:
impulse = 0.0783 kg.m/s
Explanation:
The impulse is the product of the force and an interval of time. This can be represented in terms of the mass of the body and the change in the velocity of the body in such a time:
[tex]F\Delta t=m\Delta v[/tex] [tex]=|m(v_f-v_i)|[/tex]
m: mass of the body = 2.7gm = 0.0027 kg
vf: final velocity = -14m/s
vi: initial velocity = 15m/s
vf is negative because the direction of the ball is opposite to the initial direction:
[tex]|m(v_f-v_i)|=|(0.0027kg)(-14m/s-15m/s)|=0.0783\frac{kg.m}{s}[/tex]
hence, the impulse of the ping pong ball is 0.0783 kg.m/s
