Christine has a motion detector light which gets activated an average of 16 times every 2 hours during the night. In order to find the probability that the motion detector light will be activated more than 4 times in a 25 minute period during the night using the Poisson distribution, what is the average number of activations per 25 minutes?

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Answer:

The average number of activations per 25 minutes is 2.5.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!} [/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

In this question:

For 2 hours = 2*60 = 120 minutes, the mean is 16 times.

To find for 25 minutes, we use a rule of three.

120 minutes - 16 times

25 minutes - m times

[tex]120m = 12*25[/tex]

[tex]m = \frac{12*25}{120}[/tex]

[tex]m = 2.5[/tex]

The average number of activations per 25 minutes is 2.5.