The half-life of radium-226 is 1590 years. (a) A sample of radium-226 has a mass of 50 mg. Find a formula for the mass of the sample that remains after t years. (b) Find the mass after 500 years correct to the nearest milligram. (c) When will the mass be reduced to 40 mg

Respuesta :

Answer:

Explanation:

a )

m = m₀ [tex]e^{-\lambda t[/tex]

m is mass after time t . original mass is m₀ , λ is disintegration constant

λ = .693 / half life

= .693 / 1590

= .0004358

m = m₀ [tex]e^{- 0.0004358 t}[/tex]

b )

m = 50 x [tex]e^{-.0004358\times 500}[/tex]

= 40.21 mg .

c )

40 = 50 [tex]e^{-.0004358t[/tex]

.8 = [tex]e^{-.0004358t[/tex]

[tex]e^{.0004358t[/tex] = 1.25

.0004358 t = .22314

t = 512 years .