Answer:
120 ft at 0 seconds
Question 2: 12.5 seconds in the air
Step-by-step explanation:
h(x)= -16x^2+120
We want to find the vertex
The vertex is at
h = -b/2a = 0/-32 = 0
The maximum is at 0
h(0) = 0+120 = 120
it occurs at 0 seconds and a height of 120 ft
h(x)= -16x^2+200x
We want to find the zeros of the function
0= -16x^2+200x
Factor out -8x
0 = -8x(2x -25)
Using the zero product property
-8x=0 2x-25 =0
x =0 2x =25
x=25/2
The ball starts on the ground at 0 seconds and lands at 12.5 seconds