The function f determines the volume of the box (in cubic inches) given a cutout length (in inches). Use function notation to represent the volume of the box (in cubic inches) when the cutout length is 0.2 inches. Use function notation to represent the volume of the box (in cubic inches) when the cutout length is 1.3 inches. Use function notation to represent how much the volume of the box (in cubic inches) changes by if the cutout length increases from 0.2 inches to 1.3 inches. Use function notation to represent how much the volume of the box (in cubic inches) changes by if the cutout length increases from 5.5 inches to 5.6 inches.

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Complete Question

A box is formed by cutting squares from the four corners of a sheet of paper and folding up the sides. However, the size of the paper is unknown!

Answer:

(a)[tex]f(0.2)=0.2(l-0.4)(w-0.4)[/tex]

(b)[tex]f(1.3)=1.3(l-2.6)(w-2.6)[/tex]

(c)f(1.3)-f(0.2)

(d) f(5.6)-f(5.5)

Step-by-step explanation:

Let the Length of the paper =l  (in inches)

Let the Width of the paper =w  (in inches)

Let the length of the cutout square = x (in inches)

  • Base Length of the Box = l-2x
  • Base Width of the box =w-2x
  • Height of the box =x

Volume of the box: [tex]f(x)=x(l-2x)(w-2x)[/tex]

(a)When the cutout length is 0.2 inches.

x=0.2

Volume of the box (in cubic inches) ,

[tex]f(0.2)=0.2(l-0.4)(w-0.4)[/tex]

(b)When the cutout length is 01.3 inches.

x=1.3

Volume of the box (in cubic inches) ,

[tex]f(1.3)=1.3(l-2.6)(w-2.6)[/tex]

(c)If the cutout length increases from 0.2 inches to 1.3 inches.

Change In volume (in cubic inches):

[tex]f(1.3)-f(0.2)\\=1.3(l-2.6)(w-2.6)-0.2(l-0.4)(w-0.4)[/tex]

(d)If the cutout length increases from 5.5 inches to 5.6 inches.

Change In volume (in cubic inches):

[tex]f(5.6)-f(5.5)\\=5.6(l-11.2)(w-11.2)-5.5(l-11)(w-11)[/tex]