Answer:
Step-by-step explanation:
The given data is expressed as
1204, 1206, 1345, 1306, 1207, 1078, 1357, 1232, 1228, 1302, 1189, 1177, 1083, 1094, 1326, 1071, 1427, 1348, 1420, 1253, 1270
The number of items in the data, n is 21. The lowest value is 1071 while the highest value is 1427. The convenient starting point would be 1070.5 and the convenient ending point would be 1427.5
The number of class intervals is
√n = √21 = 4.5
Approximately 5
The width of each class interval is
(1427.5 - 1070.5)/5 = 72
The end of each class interval would be
1070.5 + 72 = 1142.5
1142.5 + 72 = 1214.5
1214.5 + 72 = 1286.5
1286.5 + 72 = 1358.5
1358.5 + 72 = 1430.5
The frequency for the fifth class, that is between 1358.5 to 1430.5 would be 2
