Calcium chloride reacts with sodium hydroxide to form solid calcium hydroxide, Ca(OH)2. The balanced net ionic equation is


Group of answer choices


Ca+2(aq) + 2OH-(aq) + 2 Na+(aq) + 2 Cl-(aq) → Ca(OH)2(s).


Ca+2(aq) + 2OH-(aq) + Na+(aq) + Cl-(aq) → Ca(OH)2(s).


Ca+2(aq) + 2OH-(aq) → Ca(OH)2(s).


CaCl2(aq) + 2NaOH(aq) → CaOH(s) + NaCl(aq).


CaCl2(aq) + 2NaOH(aq) → Ca(OH)2(s) + 2NaCl(aq).

Respuesta :

Answer:

Ca²⁺ + 2 OH⁻ → Ca(OH)₂(s)

Explanation:

In chemistry, the net ionic equation is a way to write a chemical reaction whereas you write only the ions that are involved in the reaction.

When calcium chloride, CaCl₂ reacts with sodium hydroxide, NaOH to produce Ca(OH)₂ the only ions involved in the reaction are Ca²⁺ and OH⁻, thus, the balanced net ionic equation is:

Ca²⁺ + 2 OH⁻ → Ca(OH)₂(s)

Cl⁻ and Na⁺ are not involved in the reaction and you don't have to write them.

The balanced net ionic equation for the reaction between calcium chloride and sodium hydroxide is

Ca²⁺(aq) + 2OH⁻(aq) —> Ca(OH)₂(s)

The ionic equation for the reaction between calcium chloride and sodium hydroxide can be written as follow:

Calcium chloride => CaCl₂

Sodium hydroxide => NaOH

In solution,

CaCl₂(aq) —> Ca²⁺(aq) + 2Cl⁻(aq)

NaOH(aq) —> Na⁺(aq) + OH⁻(aq)

CaCl₂(aq) + NaOH(aq) —>

Ca²⁺(aq) + 2Cl⁻(aq) + Na⁺(aq) + OH⁻(aq) —> Ca(OH)₂(s) + 2Cl⁻(aq) + Na⁺(aq)

Cancel the spectator ions (i.e Cl⁻ and Na⁺) and write 2 before OH⁻ to obtain the net ionic equation as shown below:

Ca²⁺(aq) + 2OH⁻(aq) —> Ca(OH)₂(s)

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