Respuesta :

Answer:

274K

Explanation:

samueladesida43

The temperature of a sample of nitrogen gas with a mole or 0.800 mol and volume of 3.00 L is 27.43K.

How to calculate temperature?

The temperature of a gas can be calculated using the ideal gas law equation as follows:

PV = nRT

Where;

  • P = pressure
  • V = volume
  • n = number of moles
  • R = gas law constant
  • T = temperature

0.600 × 30 = 0.8 × 0.0821 × T

18 = 0.656T

T = 18 ÷ 0.656

T = 27.43K

Therefore, the temperature of a sample of nitrogen gas with a mole or 0.800 mol and volume of 3.00 L is 27.43K.

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