Respuesta :
Answer:
A) 1.67 x 10 ⁻⁶ m/s
B)5.59 x [tex]10^-^9[/tex] %
Explanation:
A)
Given:
d = 5.0 km,
mₐ = 2.5 x [tex]10^1^4[/tex] kg
u₁ = 4.0 x 10⁴ m/s
[tex]m_n[/tex] = 5.98 x 10 ²⁴ kg
Solve using kinetic conserved energy
mₐ x u₁ + [tex]m_n[/tex] x u₂ = uₓ x (mₐ + [tex]m_n[/tex] )
(2.5 x [tex]10^1^4[/tex]) (4.0 x 10⁴ )+ (5.98 x 10 ²⁴ )(0) = uₓ x (2.5 x [tex]10^1^4[/tex] + 5.98 x 10 ²⁴ )
uₓ = ( 2.5 x [tex]10^1^4[/tex] x 4.0 x 10⁴ ) / (2.5 x [tex]10^1^4[/tex] + 5.98 x 10 ²⁴ )
uₓ = 1.67 x 10 ⁻⁶ m/s
B) Assuming earth radius as a R = 1.5 x 10 ¹¹ m
t = 365 days x 24 hr / 1 day x 60 minute / 1 hr x 60s / 1 minute = 31536000 s
t = 31536000 s
D = 2 π R = 2 π( 1.5 x 10 ¹¹ )
D = 9.4247 x 10 ¹¹ m
u₂ = D / t = 9.4247 x 10 ¹¹ / 31536000
u₂ = 29885.775 m/s
% = ( 1.67 x 10 ⁻⁶ m/s ) / (29885.775 m/s) x 100
% = 5.59 x [tex]10^-^9[/tex] %
Answer:
1.67 x 10 ⁻⁶ m/s
i think thats your answer
i did the problem an got that so like
I hope I helped :D
Explanation: